# To lift a wire ring of radius 1.75 cm from the surface of a container of blood plasma, a vertical...

## Question:

To lift a wire ring of radius 1.75 cm from the surface of a container of blood plasma, a vertical force of {eq}1.61 \times 10^{-2} {/eq} N greater than the weight of the ring is required. Calculate the surface tension of blood plasma from this information.

## Force:

The hindrance, which causes the body to lose the state of inertia or the body tends to lose the state of inertia, is termed as a force. The force cab is a balanced force or unbalanced force depending on the condition of the application of force.

## Answer and Explanation: 1

**Given data**

- The value of the radius of the ring is {eq}r = 1.75\;{\rm{cm}} = 0.0175\;{\rm{m}}. {/eq}

- The value of the vertical force is {eq}{F_v} = 1.61 \times {10^{ - 2}}\;{\rm{N}}. {/eq}

The expression for the effective length is,

{eq}\begin{align*} {l_e} &= 2C\\ &= 2\left( {2\pi r} \right) \end{align*} {/eq}

Substitute the value in the above equation.

{eq}\begin{align*} {l_e} &= 2\left( {2\pi \left( {0.0175} \right)} \right)\\ &= 0.2199\;{\rm{m}} \end{align*} {/eq}

The expression for the surface tension is,

{eq}T = {F_v} \times {l_e} {/eq}

Substitute the value in the above equation.

{eq}\begin{align*} T &= 1.62 \times {10^{ - 2}} \times 0.2199\\ &= 3.56 \times {10^{ - 3}}\;{\rm{N}}{\rm{.m}} \end{align*} {/eq}

Thus, the value of the surface tension is {eq}3.56 \times {10^{ - 3}}\;{\rm{N}}{\rm{.m}}. {/eq}

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Chapter 5 / Lesson 5Force is everywhere and it comes in a variety of sizes, directions, and types. In this video lesson, you'll identify force as well the different types of force that objects may experience.