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TV broadcast antennas are the tallest artificial structures on Earth. In 1987, a 65.0 kg...

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{eq}TV {/eq} broadcast antennas are the tallest artificial structures on Earth. In {eq}1987 {/eq}, a {eq}65.0 \ kg {/eq} physicist placed himself and {eq}400 \ kg {/eq} of equipment at the top of one {eq}610 \ m {/eq} high antenna to perform gravity experiments. By how much (in {eq}mm {/eq}) was the antenna compressed, if we consider it to be equivalent to a steel cylinder {eq}0.160 \ m {/eq} in radius?

Hooke's law

The weight of physicist and equipments (W) gives a downward force on the antenna, which is balanced by normal reaction force (N') from the ground on the antenna. So, weight force W and normal force N' are responsible for compressing the antenna.

Answer and Explanation: 1

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Total weight on top of antenna W = (65+400)*9.8 N = 4557 N

Cross section area of antenna {eq}A = \pi r^2 = 3.14* 0.16*0.16 = 0.080384\ m^2 {/eq}

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