# Two pendulum bobs have equal masses and lengths (5.50 m). Bob A is initially held horizontally...

## Question:

Two pendulum bobs have equal masses and lengths (5.50 m). Bob A is initially held horizontally while bob B hangs vertically at rest. Bob A is released and collides elastically with bob B.

How fast is bob B moving immediately after the collision?

## Conservation of Energy and Momentum:

This problem follows the conversion of potential energy ({eq}U=mgh {/eq}, where m is the mass, g is acceleration due to gravity, and h is the height of the particle) into kinetic energy ({eq}K = \frac{1}{2}mv^2 {/eq}, where v is the velocity of the particle) for bob "A". We then can determine the final state of bob "B" after the collision between bob "A" and bob "B" through conservation of kinetic energy and momentum.

Let's start by defining 3 different states for this problem:

State 1: The initial state as described in the question above.

State 2: Immediately...

Become a Study.com member to unlock this answer! Create your account