Two-point charges + 8q and q are located at x = 0 and x = L respectively. The location of a point...

Question:

Two-point charges + 8q and q are located at x = 0 and x = L respectively. The location of a point on the x-axis at which the net electric field due to these two point charges is zero is

(a) L/4

(b) 2L

(d) 8 L

Electric Field Due to Stationary Charge:

Consider a stationary particle having charge {eq}q {/eq} C kept at the position vector {eq}\overrightarrow{x} {/eq}. Then due to this particle, the electric field at a point with position vector {eq}\overrightarrow{p} {/eq} is given by $$\overrightarrow{E} = \frac{q (\overrightarrow{p} - \overrightarrow{x})}{4\pi \epsilon_0 |\overrightarrow{p}-\overrightarrow{x}|^3} $$

Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

View this answer

Charge +8q is kept at x = 0, and charge +q is kept at x = L. Since both these charges are positive, therefore the electric field due to them will be...

See full answer below.

Try it risk-free for 30 days

Try it risk-free