Use technology to find the P-value for a right-tailed test with n = 23 and test statistic t = 3.422.

Question:

Use technology to find the P-value for a right-tailed test with {eq}n = 23 {/eq} and test statistic {eq}t = 3.422 {/eq}.

t-Distribution:

t-distribution is sampling distribution with (n-1). For the large degree of freedom, t distribution will be normal distribution. An excel function of t distribution TDIST() is used to get the value of P-value for the right-tailed.

Answer and Explanation:

Given that,

  • Sample size, {eq}n = 23 {/eq}
  • Test statistic, {eq}t = 3.422 {/eq}

Degree of freedom, {eq}n-1 = 23-1 = 22 {/eq}

Excel function for the P-value at right-tailed:

=TDIST(3.422,22,1)

So,

{eq}\fbox{P-value = 0.00122} {/eq}


Learn more about this topic:

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How to Find P-Value

from Business Math: Help and Review

Chapter 6 / Lesson 9
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