What is the amount of heat energy required to convert 5 g of ice at 0-degree centigrade into...

Question:

What is the amount of heat energy required to convert 5 g of ice at 0-degree centigrade into water at 40-degree centigrade?

Heat transfer

Heat provided to the fluid is equal to the product of the mass of the fluid, specific heat of the fluid, and the temperature difference. The heat that is required to change the phase of the then it is known as latent heat.

Answer and Explanation:

Given

Mass of the ice (m) = 5 g

The initial temperature of the ice {eq}T_{i} = 0^\circ {/eq}

Now, the heat required to change in the water of {eq}T_{f} = 40^\circ {/eq} would be

{eq}Q = mL + mC(T_{f} - T_{i}) \\ Q = 5*334 + 5*4.18*(40-0) \\ Q = 2506 \ J {/eq}

Where

  • L = 334 J/g is the latent heat of fusion
  • C is the specifc heat of water

Learn more about this topic:

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Thermal Expansion & Heat Transfer

from High School Physics: Help and Review

Chapter 17 / Lesson 12
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