What is the kinetic energy in eV of an electron whose de Broglie wavelength is 19% of the...
Question:
What is the kinetic energy in eV of an electron whose de Broglie wavelength is 19% of the wavelength of a photon having the energy equal to electrons kinetic energy?
Wave-particle Duality:
This principle states that every particle in the universe can be treated as a wave as well as a particle. This principle laid the foundation of Quantum Mechanics. The first verification of this principle came from the electron diffraction experiment in which the electrons acted as a wave rather than a finite-sized particle.
The de-Broglie wavelength of a particle is the wavelength of the wave which represents the particle. This wavelength depends only on the momentum of the particle.
Since the kinetic energy of a particle depends on its momentum, and momentum is related to the de-Broglie wavelength of the particle, the kinetic energy of the particle is also related to its de Broglie wavelength.
For light, the particle is called 'photon'. The energy a photon depends on the frequency of the light. This assumption was first made by Max Planck to solve the famous Black Body problem.
Answer and Explanation: 1
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The wavelength, {eq}\lambda_e {/eq}, of the electron, is {eq}19% {/eq} of the wavelength of the photon, {eq}\lambda {/eq}.
Therefore,...
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Chapter 23 / Lesson 2Wave-particle duality means that light and sub-atomic particles can also behave as waves, hence the duality. Study the definition of wave-particle duality, the Davisson-Germer Experiment, the de Broglie wavelength, and an example calculation.
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