What is the mass of 1.30 times 10^{-4} mol of Li_2CO_3?


What is the mass of {eq}1.30 \times 10^{-4}\ mol {/eq} of {eq}\rm Li_2CO_3 {/eq}?

Molar Mass:

The molar mass provides the total mass per mole of a substance. We can use this quantity in order to acquire the mass of a substance given the number of moles. This quantity is very helpful in the preparation of reagents during Chemistry experiments.

Answer and Explanation:

Determine the mass of the given number of moles of {eq}\displaystyle Li_2CO_3 {/eq} by multiplying it to the molar mass of the compound.

{eq}\begin{align} \displaystyle 1.30\times 10^{-4}\ mol\ Li_2CO_3\times 73.891\ \rm{g/mol} = 9.61\times 10^{-3}\ g\ Li_2CO_3 \end{align} {/eq}

Learn more about this topic:

What is Molar Mass? - Definition, Formula & Examples

from General Studies Science: Help & Review

Chapter 27 / Lesson 24

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