# When a 29.0-V emf device is placed across two resistors in series, a current of 11.0 A is flowing...

## Question:

When a 29.0-V emf device is placed across two resistors in series, a current of 11.0 A is flowing in each of the resistors. When the same emf device is placed across the same two resistors in parallel, the current through the emf device is 53.0 A. What is the magnitude of the larger of the two resistances?

## Resistors in series and in parallel:

Resistors can be connected in an electric circuit either in series or in parallel. In series combination of resistors the current passing through each resistor is the same but the potential difference across each resistor is different. The equivalent resistance of the series combination of resistors is given by;

{eq}\boxed{R_{eq} = R_1 +R_2+ R_3+ ............} {/eq}

where;

- {eq}R_1, \ R_2, \ R_3 , ......... {/eq} are the resistances of the individual resistors.

In parallel combination of resistors the potential difference across each resistor is the same but current passing through each resistor is different. The equivalent resistance in parallel combination is given by;

{eq}\displaystyle \boxed{\frac{1}{R_{eq}} = \frac{1}{R_1} +\frac{1}{R_2}+\frac{1}{R_3}+.....} {/eq}

## Answer and Explanation:

**Given data:**

- {eq}\displaystyle V = 29\ V {/eq} is the applied emf

- {eq}\displaystyle I = 29\ A {/eq} is the current when the resistors are in series

- ...

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from General Studies Science: Help & Review

Chapter 3 / Lesson 10