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When a 5.0-kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length....

Question:

When a {eq}\rm 5.0-kg {/eq} box is hung from a spring, the spring stretches to {eq}\rm 50\ mm {/eq} beyond its relaxed length. In an elevator accelerating upward at {eq}\rm 2.0\ m^2 {/eq}, how far does the spring stretch with the same box attached?

Spring Constant:

The spring constant is the measure of the stiffness of the spring. The lower the value of spring constant, is spring is less stiff (easier to stretch). The measurement unit of spring constant is a newton per meter.

Answer and Explanation:

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Given Data

  • The mass of the box is {eq}m = 5\;{\rm{kg}} {/eq}.
  • The stretch of spring is {eq}\Delta x = 50\;{\rm{mm}} {/eq}.
  • The acceleration of...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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