When a hot objects is placed in a water bath whose temperature is 25^{\circ}C, it cools from...

Question:

When a hot objects is placed in a water bath whose temperature is 25{eq}^{\circ}{/eq}C, it cools from 100{eq}^{\circ}{/eq} to 50{eq}^{\circ}{/eq} in 195 s. In another bath, the same cooling occurs in 175 s. Find the temperature of the second bath.

Newton's Law of Cooling

This problem is an application of Newton's Law of Cooling. We are going to use the equation for newton's law of cooling with the given initial conditions to determine the constants of the equation followed by determining the temperature of the second bath.

Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

View this answer


It is given that the initial temperature is, {eq}\displaystyle T_0=25^\circ {/eq}

The temperature of the object is given by,

{eq}\displaystyle...

See full answer below.


Learn more about this topic:

Loading...
First-Order Linear Differential Equations

from

Chapter 16 / Lesson 3
1.9K

In this lesson you'll learn how to solve a first-order linear differential equation. We first define what such an equation is, and then we give the algorithm for solving one of that form. Specific examples follow the more general description of the method.


Related to this Question

Explore our homework questions and answers library