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When a solid object is completely submerged in ethyl alcohol, its apparent weight is 17.2 N and...

Question:

When a solid object is completely submerged in ethyl alcohol, its apparent weight is 17.2 N and when completely submerged in water, its apparent weight is 13.4 N. Determine the volume of the object. Use 790 kg/{eq}m^3 {/eq} as the density of the ethyl alcohol and 1000 kg/{eq}m^3 {/eq} as the density of water.

Apparent Weight For the Body Submerged In Fluid:

Apparent weight is different from the actual weight of the body and it depends on the buoyancy force applied on the body when the object is submerged inside the fluid. Apapernt weight is the differnce between the actual weight of the body and the buoyancy force applied on the body.

For the expression of apparent weight:

{eq}W_a=W-F_b {/eq}

Here, the apparent weight of the object is {eq}W_a {/eq}

Buoyancy force applied to the body is {eq}F_b {/eq}

Answer and Explanation:

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Given:

  • The apparent weight of the body when immersed in the water is {eq}W_{a1}=13.4\ N {/eq}
  • The apparent weight of the body when immersed in the...

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Archimedes' Principle: Definition, Formula & Examples

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Chapter 19 / Lesson 4
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Archimedes' principle deals with the forces applied to objects by the fluids around that object. This applied force reduces the net weight of any object in a fluid, whether it be a liquid or a gas.


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