# When you dive from atop a tall flagpole into a swimming pool below. Your potential energy at the...

## Question:

When you dive from atop a tall flagpole into a swimming pool below. Your potential energy at the top is 14000 J (relative to the surface of the pool). What is your kinetic energy when his potential energy reduces to 1000 J?

## Conservation of energy:

Conservation of energy states that if no external force is working on a system then total energy of the system remain conserve. At the top diver has only potential energy but no kinetic energy. When he jumps, his potential energy starts to convert into kinetic energy but total energy always remain constant.

This conservation will help us to solve the problem.

{eq}\textbf{Answer:}\text{ My kinetic energy is }\color{red}{13,000\ \rm J}\text{ when potential energy reduced to 1000 J.} {/eq}

{eq}\textbf{Explanation:} {/eq}

• Initially at the top potential energy {eq}P=14000\ \rm J {/eq}
• Kinetic energy at the top {eq}K=0 {/eq}

Hence total energy at the top {eq}E=P+K=14000+0=14,000\ \rm J {/eq}

From conservation of energy total energy always {eq}E=14000\ \rm J {/eq}

Let when potential energy is {eq}P=1000\ \rm J {/eq} then kinetic energy energy is {eq}K' {/eq}

Therefore {eq}P'+K'=E\\ K'=E-P'\\ K'=14000-1000\\ K'=13000\ \rm J {/eq} 