# You are given 850 ml glucose stock solution with the concentration 1 M. How would you make 1 L of...

## Question:

You are given 850 ml glucose stock solution with the concentration 1 M. How would you make 1 L of 200 mM glucose solution?

## Solubility of Glucose:

Glucose is a polar organic molecule that contains a polar aldehyde group and various polar protic hydroxyl groups. Hence, glucose dissolves in a polar protic solvent. e.g., water quite easily. The dissolution of glucose in water is an endothermic process.

According to the law of dilution:

{eq}\rm C_1V_1=C_2V_2 {/eq}

Where:

{eq}\rm C_1 {/eq} is the concentration of the stock solution.

{eq}\rm V_1 {/eq} is the volume of the stock solution required to make the diluted solution.

{eq}\rm C_2 {/eq} is the concentration of the diluted solution.

{eq}\rm V_2 {/eq} is the volume of the diluted solution.

Given:

{eq}\rm C_1=1\;M\\ \rm C_2=200\;mM=200\times 10^{-3}\;M\;\;;(1\;mM=10^{-3}\;M)\\ \rm V_2=1\;L=1000\;mL {/eq}

Substituting the above values, we get:

{eq}\rm (1\;M)\times V_1=(200\times 10^{-3}\;M)\times (1000\;mL)\\ \rm \Rightarrow V_1=200\;mL {/eq}

Procedure:

Pipette out 200 mL of 1 M stock solution of glucose and place it in a 1L volumetric flask. Then add a sufficient amount of water to reach the "1L" calibration mark.

Calculating Dilution of Solutions

from

Chapter 8 / Lesson 5
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Learn what a solution is and how to properly dilute a new solution from a stock solution. Learn the dilution equation that combines molarity, the volume of stock solution and desired solution to determine how much stock solution is needed for the new solution.