# You throw a small stone straight upward at 40 m/s. (a) How high will it rise? (b) How long does...

## Question:

You throw a small stone straight upward at 40 m/s.

(a) How high will it rise?

(b) How long does it take to reach its maximum height?

## Vertical motion under gravity:

When an object is thrown straight up from the surface of the earth with some initial speed, its speed goes on decreasing until it reaches the highest point of its path at which it's speed becomes zero momentarily. The object then falls freely under gravity and its speed goes on increasing as it approaches the ground. Finally it reaches the ground with the same speed with which it was initially thrown upward. Kinematic equations used for linear motion are also applicable to the vertical motion, with acceleration due to gravity replacing the acceleration in the equations.

## Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

View this answer**Given data:**

- {eq}v_0 = 40 \ m/s {/eq} is the initial speed of the stone

**Part (a) :**

- Let, {eq}h_{max} {/eq} be the maximum height achieved by the...

See full answer below.

#### Ask a question

Our experts can answer your tough homework and study questions.

Ask a question Ask a question#### Search Answers

#### Learn more about this topic:

from

Chapter 7 / Lesson 3Kinematic quantities are calculated using the 'big 5' equations that explain a motion in constant acceleration, when in a straight line. Learn each of these variables and how they fit into example calculations provided.