# Graphing Derivatives & L'Hopital's Rule Flashcards

*Try it risk-free for 30 days. Cancel anytime.*

###### Already registered? Login here for access

*x*= -2 and

*x*= 5, if the function has a maximum at

*x*= -2 and a minimum at

*x*= 5.

*x*-values is 0.

*x*= 1, the original function

*f*(

*x*) has a tangent line with a slope of -3.

*f*(

*x*) has a slope of 7. Use this information to make a statement about a point on the graph of

*f*'(

*x*).

*f*'(

*x*) contains the point (-1, 7)

*f*(

*x*) has one minimum at

*x*= 1.

*f*'(

*x*), find

*f*(

*x*)

*f*(

*x*) = -1.5

*x*2 + 6

*x*+

*c*, where

*c*can be any constant

*x*= 2 is 5. Determine the value of the derivative of that function at

*x*= 2.

*x*= 2

*x*-values where

*f*'(

*x*) = 0

*f*'(

*x*) would equal zero at

*x*= -2, 0.5, 3

*x*-value where the function has a minimum or a maximum, the derivative will equal 0.

*f*(

*x*) and that of

*f*'(

*x*).

*f*(

*x*) and the orange curve is its derivative

*f*'(

*x*).

### Ready to move on?

## Flashcard Content Overview

These flashcards contain practice problems for two different topics of calculus: Graphs of Derivatives and L'Hopital's Rule. You will be able to review how to use derivatives to determine extrema and concavity of functions. Additionally, you will be able to practice using derivatives to find limits by applying L'Hopital's Rule to a variety of functions.

*f*(

*x*) and that of

*f*'(

*x*).

*f*(

*x*) and the orange curve is its derivative

*f*'(

*x*).

*x*-value where the function has a minimum or a maximum, the derivative will equal 0.

*x*-values where

*f*'(

*x*) = 0

*f*'(

*x*) would equal zero at

*x*= -2, 0.5, 3

*x*= 2 is 5. Determine the value of the derivative of that function at

*x*= 2.

*x*= 2

*f*'(

*x*), find

*f*(

*x*)

*f*(

*x*) = -1.5

*x*2 + 6

*x*+

*c*, where

*c*can be any constant

*f*(

*x*) has one minimum at

*x*= 1.

*f*(

*x*) has a slope of 7. Use this information to make a statement about a point on the graph of

*f*'(

*x*).

*f*'(

*x*) contains the point (-1, 7)

*x*= 1, the original function

*f*(

*x*) has a tangent line with a slope of -3.

*x*= -2 and

*x*= 5, if the function has a maximum at

*x*= -2 and a minimum at

*x*= 5.

*x*-values is 0.

*x*= 1.

*x*= 0.

*f*(

*x*) = -

*x*3 + 3

*x*2 in the interval from

*x*= 1 to

*x*= 3.

*y*= 2

*x*3 + 4

*x*2 - 7

*x*= 0 and

*x*= 4/3

*a*and

*b*for the function

*f*(

*x*) =

*ax*3 -

*bx*2 if the point (1, -1) is a local minimum of

*f*(

*x*).

*a*= 2 and

*b*= 3

*f*(

*x*) =

*x*5 - 4

*x*3

To unlock this flashcard set you must be a Study.com Member.

Create
your account

Back To Course

Math 104: Calculus16 chapters | 135 lessons | 11 flashcard sets

- Go to Continuity

- Go to Series

- Go to Limits

- Graphing Functions Flashcards
- Function Continuity Flashcards
- Geometry & Trigonometry Flashcards
- Limits in Calculus Flashcards
- Rate of Change in Calculus Flashcards
- Solving Derivatives Flashcards
- Graphing Derivatives & L'Hopital's Rule Flashcards
- Integrals & the Area Under the Curve Flashcards
- Integration in Calculus Flashcards
- Differential Equations Flashcards
- Math 104: Calculus Formulas & Properties
- Go to Studying for Math 104