Login
Copyright

Direct and Inverse Variation Problems: Definition & Examples

An error occurred trying to load this video.

Try refreshing the page, or contact customer support.

Coming up next: How to Solve Exponential Equations

You're on a roll. Keep up the good work!

Take Quiz Watch Next Lesson
 Replay
Your next lesson will play in 10 seconds
  • 0:02 Variation
  • 2:05 Example 1
  • 3:56 Example 2
  • 5:36 Lesson Summary
Add to Add to Add to

Want to watch this again later?

Log in or sign up to add this lesson to a Custom Course.

Login or Sign up

Timeline
Autoplay
Autoplay
Create an account to start this course today
Try it free for 5 days!
Create An Account

Recommended Lessons and Courses for You

Lesson Transcript
Instructor: Elizabeth Foster

Elizabeth has been involved with tutoring since high school and has a B.A. in Classics.

In this lesson, you'll learn how to approach questions about direct and inverse variation with a simple explanation of what the terms mean and how to apply them to problems.

Variation

Equations with direct and inverse variation sound a little intimidating, but really, they're just two different ways of talking about how one number changes relative to another number.

In direct variation, as one number increases, so does the other. This is also called direct proportion: they're the same thing. An example of this is relationship between age and height. As the age in years of a child increases, the height will also increase.

In the abstract, we can express direct variation by using the equation y = kx.

x and y are the two quantities - in our example, they'd be the age and the height of the child. k is called the constant of proportionality: it tells you specifically how much bigger y will get for every increase in x. For example, maybe y = 2x: this means that for every increase in x, y will increase by double that amount.

You can see that the bigger the number you plug in for x, the bigger the resulting value of y will be.

In inverse variation, it's exactly the opposite: as one number increases, the other decreases. This is also called inverse proportion. An example would be the relationship between time spent goofing off in class and your grade on the midterm. The more you goof off, the lower your score on the test.

If we wanted to give this one an equation, we would say:

y = k/x, where x and y are the two quantities, and k is still the constant of proportionality, telling how much one varies when the other changes.

You can see that in this equation, you divide a constant number by x to get the value of y. So the bigger the value of x, the smaller the value of y will be. That's inverse variation: as one goes up, the other goes down.

Example 1

This might seem really complicated and confusing, but just remember the two formulas: y = kx for direct variation, and y = k/x for inverse variation. As you practice with example problems, you'll learn how to apply them to specific problems.

A very simple example is a problem like this one:

The population of a certain species of bacteria varies directly with the temperature. When the temperature is 35 degrees Celsius, there are 7 million bacteria. How many millions of bacteria are there when the temperature is 38 degrees Celsius?

First of all, we can see that we'll be using the direct variation equation, y = kx.

Now let's plug in what we have from the problem:

The problem gives us two values: temperature and number of bacteria. We'll plug in the temperature for x and the number of bacteria for y. This gives us 7 = k(35).

Now all we have to do is divide to find the value of k for this particular problem: it turns out to be 0.2.

The next step is to use that value to find out how many millions of bacteria there are at 38 degrees Celsius. So, we use the equation again.

This time, we'll plug in x and k, since we're looking for y. We find that y = (0.2)(38). Do the multiplication, and we learn that y, or the value of the population in millions is 7.6. So the answer to this question would be 7.6 million bacteria.

That wasn't so painful, right? It's just about using the equations properly. Now let's try one that's a little harder.

To unlock this lesson you must be a Study.com Member.
Create your account

Register for a free trial

Are you a student or a teacher?
I am a teacher

Unlock Your Education

See for yourself why 30 million people use Study.com

Become a Study.com member and start learning now.
Become a Member  Back

Earning College Credit

Did you know… We have over 95 college courses that prepare you to earn credit by exam that is accepted by over 2,000 colleges and universities. You can test out of the first two years of college and save thousands off your degree. Anyone can earn credit-by-exam regardless of age or education level.

To learn more, visit our Earning Credit Page

Transferring credit to the school of your choice

Not sure what college you want to attend yet? Study.com has thousands of articles about every imaginable degree, area of study and career path that can help you find the school that's right for you.

Create an account to start this course today
Try it free for 5 days!
Create An Account
Support