How to Use the Rational Roots Theorem: Process & Examples

An error occurred trying to load this video.

Try refreshing the page, or contact customer support.

Coming up next: How to Evaluate a Polynomial in Function Notation

You're on a roll. Keep up the good work!

Take Quiz Watch Next Lesson
 Replay
Your next lesson will play in 10 seconds
  • 0:03 Rational Roots Theorem
  • 2:09 Possible Solutions
  • 2:40 Finding the Possibilities
  • 4:15 Finding a Solution
  • 5:45 Lesson Summary
Add to Add to Add to

Want to watch this again later?

Log in or sign up to add this lesson to a Custom Course.

Login or Sign up

Timeline
Autoplay
Autoplay
Speed

Recommended Lessons and Courses for You

Lesson Transcript
Instructor: Yuanxin (Amy) Yang Alcocer

Amy has a master's degree in secondary education and has taught math at a public charter high school.

When it comes to solving polynomials, it can sometimes be easier to begin with a list of possible solutions to try. This video lesson tells you how to form a list of possible solutions by using the rational roots theorem.

The Rational Roots Theorem

The rational roots theorem is a very useful theorem. It tells you that given a polynomial function with integer or whole number coefficients, a list of possible solutions can be found by listing the factors of the constant, or last term, over the factors of the coefficient of the leading term. Okay, that's a mouthful. Let me show you what this all means.

If you have a polynomial function such as 2x^2 + 9x + 4, then our possible solutions are -1/1, -2/1, -4/1, -1/2, -2/2, -4/2, 1/1, 2/1, 4/1, 1/2, 2/2 and 4/2. This list actually has duplicates, such as 1/1 and 2/2. Getting rid of these duplicates and simplifying, we get this list of possible solutions: -4, -2, -1, -1/2, 1/2, 1, 2 and 4.

Note that in our list, we took each and every factor of our constant term, our 4, and put it over the factors of our leading coefficient, our 2. All of our numerators are factors of the constant term, and all our denominators are factors of the leading coefficient.

We call this the rational root theorem because all these possible solutions are rational numbers. Having this list is useful because it tells us that our solutions may be in this list. In fact, we can actually check to see that our solutions are part of this list. If we factor our polynomial, we get (2x + 1)(x + 4). Our solutions are thus x = -1/2 and x = -4. As you can see, these solutions are included in our list.

So, if we didn't know where to start to find solutions to our polynomial, we can begin with the rational roots theorem to help us find the solutions. After making our list, we then can plug numbers in one at a time into our polynomial and see which one will give us an answer of 0 and, thus, be a solution.

Possible Solutions

Notice that I've been using the word 'possible' solutions. This is because the list of numbers that we get from using the rational root theorem is just that. It is a list of possibilities. As you saw from our very first example, most of the numbers will not turn out to be solutions at all. And it is also possible to get a list where none of the numbers are solutions.

When you are using this theorem to get your list of possible solutions, just remember that. You are getting a list of possibilities; you are not getting a list of solutions.

Finding the Possibilities

Let's look at this theorem in more detail now with another example. Let's try and find the possible solutions to the polynomial function x^3 - 6x^2 + 11x - 6. First, we locate our constant term, which is our last term. It is -6.

Next, we locate our leading coefficient. It is 1, since there is no number in front of the x^3 term. Now, we need to look for the factors of these two numbers. The factors of -6 are -6, -3, -2, -1, 1, 2, 3 and 6. We have both positive and negative because we can do 1 * -6 as well as -1 * 6. These factors will become our numerators.

Next, what are our factors of the leading coefficient of 1? They are -1 and 1. Remember we can do either 1 * 1 or -1 * -1. These will become our denominators. Now we can go and systematically place our numerators over our denominators one by one. We get -6/1, -3/1, -2/1, -1/1, 1/1, 2/1, 3/1 and 6/1.

We can simplify these fractions to become -6, -3, -2, -1, 1, 2, 3 and 6. If you saw this coming, then you saw that we could have stuck with just the factors of -6 because our denominator is always 1, and anything over 1 is itself.

To unlock this lesson you must be a Study.com Member.
Create your account

Register to view this lesson

Are you a student or a teacher?

Unlock Your Education

See for yourself why 30 million people use Study.com

Become a Study.com member and start learning now.
Become a Member  Back
What teachers are saying about Study.com
Try it risk-free for 30 days

Earning College Credit

Did you know… We have over 160 college courses that prepare you to earn credit by exam that is accepted by over 1,500 colleges and universities. You can test out of the first two years of college and save thousands off your degree. Anyone can earn credit-by-exam regardless of age or education level.

To learn more, visit our Earning Credit Page

Transferring credit to the school of your choice

Not sure what college you want to attend yet? Study.com has thousands of articles about every imaginable degree, area of study and career path that can help you find the school that's right for you.

Create an account to start this course today
Try it risk-free for 30 days!
Create An Account
Support