*Matthew Bergstresser*Show bio

Matthew has a Master of Arts degree in Physics Education. He has taught high school chemistry and physics for 14 years.

Lesson Transcript

Instructor:
*Matthew Bergstresser*
Show bio

Matthew has a Master of Arts degree in Physics Education. He has taught high school chemistry and physics for 14 years.

In a series circuit, the current flows through each component since there is only one path where the current can flow. Explore the properties of voltages in series circuits and learn how to calculate voltage drops using Ohm's law.
Updated: 01/19/2022

Imagine that you had to power a cart through a roller coaster by peddling a stationary bicycle. Sounds fun for your friends, but pretty miserable for you! The track starts at a high elevation, goes down hill, and then back up to where it started. Along the way, the track has rough patches resisting the movement of the cart.

This is an analogy for how a series circuit works. The track is the wire, the cart is the current flow, the rough parts of the track are resistors, and you pedaling the bicycle are the battery. Let's flesh out this analogy with an in-depth study of a series circuit.

A **series circuit** is a circuit where electrical current only has one pathway from the positive terminal of a battery, through at least one resistor, and back to the negative terminal of the battery. This diagram shows a basic, series circuit like we just described:

The battery pushes the current from the positive terminal through each resistor and back to the negative terminal. In the roller coaster analogy, you wouldn't have to pedal when the cart leaves the top of the roller coaster: gravity does the work for you. Electrical current naturally moves from high potential to low potential too, but it's electrical potential. You and the battery have to do work to make the cart and the current move from low potential back to high potential. This next diagram shows the potential difference of the battery and the resistance of each resistor:

When the current flows through a resistor there is a voltage drop. The side of the resistor closest to the high potential side of the battery (the + terminal) has higher potential than the opposite side of the resistor. The voltage drop is caused by the resistor using the electrical energy to do something such as turning a motor. We will use Ohm's law and Kirchhoff's loop rule to determine the voltage drops across the resistors.

**Ohm's law** is the equation *V* = *IR*, where *V* is for voltage in volts, *I* is for current in amperes (or amps, or A) and *R* is for resistance in ohms (or Î©). We can't use this equation alone because we don't know the current through the resistors. This is where Kirchhoff's rule comes in.

Voltage is a change in electric potential. If we start and stop at the same location in a circuit there's no change in voltage. It is like the cart moving through a flat section of the roller coaster track. The change in elevation is zero. In formal physics language, **Kirchhoff's loop rule** states that in a closed loop, the change in voltage is zero.

We have to trace a path (remember that there's only one) through the circuit and then write the voltage for each resistor and battery along the path. When we move in the direction of current flow, the voltages across the resistors are negative.

Going from the negative terminal of the battery to the positive terminal is an increase in voltage, so it's positive. Adding all of these voltages and setting it equal to zero will allow us to solve for the current in the circuit. Let's analyze our example circuit to determine the change in voltages across each resistor.

This next diagram shows the loop which we will follow in the circuit analysis:

Starting from the red dot, we move along with the current to the right and we reach the 20Î© resistor. The voltage across this resistor is negative since we're moving from the high potential side to the low potential side and is represented by -20*I*. We do the same thing for the other two resistors. This next diagram shows the voltage equation for each resistor:

When we reach the battery, we are going from the negative terminal (zero potential) to the positive terminal, which is 20 volts of electric potential. Î”V is final potential - initial potential, which is 20 V - 0 V = +20 V. Now we can add all of these voltages together and set the sum equal to zero.

-20*I* + (-30*I*) + (-40*I*) + 20 = 0

Combining like terms, and solving for *I*, we get:

-90*I* = -20

*I* â‰ˆ 0.22 A

Now we can go back to each resistor and plug in the amperage into its voltage equation as shown in this next diagram:

Notice that the sum of the voltages across each resistor roughly equals the voltage of the battery. If we didn't round the current value, the sum of the voltages across each resistor would equal the voltage of the battery.

Let's review what we've learnedâ€¦

A **series circuit** is one where there is only one path for current to take through resistors and the battery. Batteries provide a potential difference to the circuit which pushes current from the high potential side of the battery (the +, or positive, terminal), through the resistors, and back to the low potential side of the battery (the - , or negative, terminal). The resistors use the current to do something such as turn a motor.

**Ohm's law** is *V* = *IR* and **Kirchhoff's loop rule** states the sum of voltages in a closed loop must equal zero. Each voltage is negative across a resistor in a series circuit because the resistors use the electrical energy provided by the battery. When moving in a loop around the circuit starting from the positive side of the battery, each resistor's voltage is -*IR*, and the battery is the positive value of its voltage. Adding all of these voltages will give an equation with *I* as the only variable. This is how the current value is determined in the circuit, which can be plugged back into *IR* for each resistor to get its voltage drop.

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