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UExcel Physics: Study Guide & Test Prep18 chapters | 201 lessons | 13 flashcard sets

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Lesson Transcript

Instructor:
*David Wood*

David has taught Honors Physics, AP Physics, IB Physics and general science courses. He has a Masters in Education, and a Bachelors in Physics.

After watching this lesson, you will be able to explain what the parallel axis theorem is and how it is used. You will also be able to use the theorem to solve problems. A short quiz will follow.

In physics, we love to simplify situations. After all, who wants to do complex, calculus-based math and spend hour upon hour playing with algebra? Well, actually, I suppose a lot of physicists do like that. But only when it's genuinely necessary.

In other lessons, we've talked about the moment of inertia. **Rotational inertia**, otherwise known as moment of inertia, is a number that represents how much mass a rotating object has and how it is distributed. An object with more rotational inertia is harder to accelerate. Moment of inertia is measured in kilogram/meters squared.

But everything we've focused on involves situations that have nice, uniform objects. Spheres, shells, rings... anything symmetrical. And it also assumed that those objects were rotating around an axis that went straight through the center of mass of the object. But what happens when that's not the case?

Well, you could do a load of complex calculus. Or, if you don't like calculus, like most people, you could use the parallel axis theorem.

The **parallel axis theorem** states that the moment of inertia of an object around a particular axis is equal to the moment of inertia around a parallel axis that goes through the center of mass, plus the mass of the object, multiplied by the distance to that parallel axis, squared.

The moment of inertia around the center of mass is a minimum value. If you move the rotation axis elsewhere, the moment of inertia, how difficult it is to slow or speed up the rotation of the object, increases.

The parallel axis theorem is much easier to understand in equation form than in words. Here it is:

I = Icm + mr ^2

This diagram shows a randomly shaped object with a rotation axis that doesn't go through the center of mass:

But if you take a parallel rotation axis that does go through the center of mass, we can use that to figure out the moment of inertia through the actual rotation axis.

If we know, or we can figure out, the moment of inertia through the center of mass axis, *Icm*, measured in kilogram/meters squared, and we know the total mass of the object, *m*, measured in kilograms, and the distance the parallel axis is away from the center of mass, *r*, measured in meters, we can just plug those numbers in and figure out the moment of inertia through our off-center rotational axis.

So, that's probably a little easier to understand now. But you know what would make it even better? An example.

One day you're cleaning the basement when you find a really old bedroom pillow. One of those super lumpy pillows that should have been thrown out years ago. Before you throw it out, being an amateur physicist, you decide to do an experiment on it. You unceremoniously grab a knitting needle from your grandma, stab it through the middle, and spin the pillow around the needle.

You may have stuck the needle right through the middle, but because it's all lumpy and deformed, unfortunately, the center of mass of the pillow isn't in the middle any longer. The center of mass of the pillow is 0.05 meters away from the middle. If you'd stuck the knitting needle through the center of mass, the moment of inertia would have been 0.00015, but you didn't. Now you need to calculate it. If the mass of the pillow is 0.1 kilograms, what is the moment of inertia of the pillow around the knitting needle axis?

How do we solve this? Well, first of all, we should write down what we know. We know that the distance between the rotation axis and the center of mass is 0.05 meters, that's *r*. We know that the mass of the pillow is 0.1 kilograms, that's *m*. And we were told that the moment of inertia, if it was being rotated around the center of mass, would be 0.00015, that's *Icm*, the moment of inertia around the center of mass axis.

Plug those numbers into the parallel axis theorem, and you get:

*I* = 0.00015 + (0.1) (0.05) ^2.

Type it into a calculator and solve, and you get 0.0004 kilogram/meters squared.

And that's it, that's our answer.

**Rotational inertia** (otherwise known as moment of inertia) is a number that represents how much mass a rotating object has and how it is distributed. An object with more rotational inertia is harder to accelerate. Moment of inertia is measured in kilogram/meters squared.

The parallel axis theorem allows us to figure out the moment of inertia for an object that is rotating around an axis that doesn't go through the center of mass. The **parallel axis theorem** states that the moment of inertia of an object around a particular axis is equal to the moment of inertia around a parallel axis that goes through the center of mass, plus the mass of the object, multiplied by the distance to that parallel axis, squared.

The moment of inertia around the center of mass is a minimum value. If you move the rotation axis elsewhere, the moment of inertia, how difficult it is to slow or speed up the rotation of the object, increases.

This equation allows us to calculate that increased value, where *Icm* (or I-center-of-mass) is the moment of inertia if the object were rotating around a parallel axis that did go through the center of mass, measured in kilogram/meters squared, and *m* is the mass of the object, measured in kilograms, and *r* is the distance between the parallel center of mass axis and the rotation axis, measured in meters.

Each section of this lesson can prepare you to:

- Describe rotational inertia
- Explain the parallel axis theorem
- Identify the equation form of the parallel axis theorem

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6 in chapter 7 of the course:

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UExcel Physics: Study Guide & Test Prep18 chapters | 201 lessons | 13 flashcard sets

- Go to Vectors

- Go to Kinematics

- Differences Between Translational & Rotational Motion 4:33
- Rotational Kinematics: Definition & Equations 5:03
- Five Kinematics Quantities & the Big 5 Equations 6:02
- Torque: Concept, Equation & Example 4:52
- Rotational Inertia & Change of Speed 4:30
- The Parallel-Axis Theorem & the Moment of Inertia 5:30
- Rolling Motion & the Moment of Inertia 4:27
- Work & Power in Rotational Motion 4:46
- Angular Momentum vs. Linear Momentum 5:52
- Conservation of Angular Momentum 7:00
- Go to Rotational Motion

- Go to Relativity

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