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Physics: High School18 chapters | 212 lessons

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Lesson Transcript

Instructor:
*David Wood*

David has taught Honors Physics, AP Physics, IB Physics and general science courses. He has a Masters in Education, and a Bachelors in Physics.

After watching this video, you will be able to explain what electric potential is and solve problems using an expression for the electric potential of a cylinder. In AP Physics C, you should be able to derive the expression. A short quiz will follow.

**Electric potential** is the amount of electric potential energy that each unit charge would have at a particular point in space. It's measured in Joules per coulomb or volts. Two points in space have different electric potentials due to their different positions inside a field.

Since electric potential is quite hard to picture, one way to make it easier to imagine is to think in terms of something we experience every day: gravity. The gravitational potential is how much gravitational potential energy each kilogram of mass (instead of charge) would have at a particular location.

If you raise a ball to a height, *h*, and drop it, it moves because it had gravitational potential energy at that height. The amount of energy a 1 kilogram mass would have is the potential at that position. And if you drew field lines, they would point from the raised ball towards the ground - potential decreases as you follow the field lines. Electric potential works in exactly the same way.

In another lesson, we introduced Gauss' law. **Gauss' law** is used to come up with equations for the electric field created by a charged object. This could be any shape; it could be a charged sphere or, for today's lesson, a charged cylinder. Once we have an expression for electric field, we can use it to come up with an expression for electric potential.

Gauss' law says that the electric field times the area of a surface is equal to the charge enclosed by that surface divided by the permittivity of free space, which is always equal to 8.85 * 10^-12. The next step is to plug in an equation for the surface area of a particular object we're looking at.

Today, we're looking at a cylinder. But to make it easier, we're going to make it a long cylinder. By long, we mean that it's long enough that the edges of the cylinder are far away and don't affect the electric field result. For a long cylinder, the surface area is equal to the circumference of the cylinder (which is 2pi*r*) multiplied by the length of the cylinder. Plug that into Gauss' law and rearrange to make *E* the subject, and we get this equation: *E* equals *Q* over 2pi epsilon-zero *rL*.

Last of all, we need to get rid of the length because with it being a long cylinder, we don't want length to be involved. To do that, we define the charge per unit length, lambda, where lambda equals *Q* divided by *L*. Our equation already has *Q* divided by *L* in it, so we can replace that with lambda instead. When you do that, you get this final equation, where lambda is the charge density per unit length of the cylinder, epsilon-zero is a constant that is always equal to 8.85 * 10^-12, and *r* is the distance you are from the center of the cylinder.

But we don't want an equation for electric field, we want an equation for the electric potential. To get this, we would have to do some calculus. The integral of the electric field with respect to the radius will give us the potential. So, we have to integrate the equation we have so far with respect to *r*.

We also have to define zero potential as being at the surface of the cylinder - this is completely arbitrary, but we need to have some kind of zero point. If we do that, we get this final equation for the potential outside of a charged cylinder:

Most of these terms we've defined before, but uppercase *R* is the radius of the cylinder, and lowercase *r* is the radius you're trying to find the potential at.

So, for example, you could be asked the following: 'A long, conductive cylinder has a charge of 0.1 coulombs per meter and a radius of 0.02 meters. What is the electric potential at a radius of 0.1 meters away from the center of the cylinder?'

First of all, we need to write down what we know. The charge per unit length, lambda, is equal to 0.1, and the radius of the cylinder itself, uppercase *R*, is 0.02. We also know that the radius we're interested in, lowercase *r*, is 0.1. So, all we have to do is plug these numbers into the equation and solve for the potential, *V*. Doing that will give us a potential of negative 2.9 * 10^9 volts. And that's it - that's our answer.

**Electric potential** is the amount of electric potential energy that each unit charge would have at a particular point in space. It's measured in Joules per coulomb or volts. Two points in space have different electric potentials due to their different positions inside a field.

One way to find the electric potential of a long cylinder is to first use **Gauss' law** to find an expression for the electric field. When we do that, we get this expression:

And then if we integrate that expression with respect to the radius, and apply the limit that *V* = 0 at the surface of the cylinder, we get this final equation for the potential of a long cylinder:

Here, lambda is the charge density per unit length of the cylinder, measured in coulombs per meter; epsilon-zero is a constant that is always equal to 8.85 * 10^-12; lowercase *r* is the distance you are from the center of the cylinder; and uppercase *R* is the radius of the cylinder itself.

Strengthen your ability to do the following by reviewing this lesson on the potential of a cylinder:

- Characterize electric potential
- Use Gauss' law when finding electric potential of a cylinder
- Arrive at the final equation for the potential of a long cylinder

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Physics: High School18 chapters | 212 lessons

- Electric Field & the Movement of Charge 6:41
- Voltage Sources: Energy Conversion and Examples 8:33
- Electric Potential Energy: Definition & Formula 4:19
- Electric Potential: Charge Collections and Volt Unit 4:38
- Finding the Electric Potential Difference Between Two Points 5:31
- What is Capacitance? - Definition, Equation & Examples 4:29
- Capacitance: Units & Formula 6:00
- Fixed & Variable Capacitors: Parts & Types
- Capacitors: Construction, Charging & Discharging 6:00
- Ohm's Law: Definition & Relationship Between Voltage, Current & Resistance 7:17
- The Potential of a Sphere 4:17
- The Potential of a Cylinder 5:14
- Go to Potential and Capacitance in Physics

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