# Calculating the Magnetic Force Perpendicular to the Direction of a Charge

• 1.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}5.2\times 10^6\ m/s {/eq} towards a magnetic field formed by two magnets of 1.8 T. Calculate the magnetic force that the electron experiences.

• {eq}3.5\times 10^{-12}\ N {/eq}

• {eq}0.5\times 10^{-12}\ N {/eq}

• {eq}2.5\times 10^{-12}\ N {/eq}

• {eq}1.5\times 10^{-12}\ N {/eq}

• 2.

What will be the magnetic force that has a particle charged with {eq}2.31\times 10^{-19} C {/eq} moving perpendicular to {eq}7.62\times 10^6\ m/s {/eq} towards a magnetic field of 4.3 T.

• {eq}7.6\times 10^{-12}\ N {/eq}

• {eq}6.3\times 10^{-12}\ N {/eq}

• {eq}5.8\times 10^{-12}\ N {/eq}

• {eq}6.7\times 10^{-12}\ N {/eq}

• 3.

A proton with a charge of {eq}1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}5\times 10^6\ m/s {/eq} and it moves to a magnetic field formed by a TV of 2.3 T. Determine the magnetic force that the proton experiences.

• {eq}0.3\times 10^{-12}\ N {/eq}

• {eq}1.8\times 10^{-12}\ N {/eq}

• {eq}0.6\times 10^{-12}\ N {/eq}

• {eq}1.1\times 10^{-12}\ N {/eq}

• 4.

Calculate the magnetic force that a particle with a charge of {eq}3.54\times 10^{-19} C {/eq} experiences and that moves perpendicularly at {eq}4.6\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 3.3 T.

• {eq}5.2\times 10^{-12}\ N {/eq}

• {eq}5.5\times 10^{-12}\ N {/eq}

• {eq}5.4\times 10^{-12}\ N {/eq}

• {eq}5.6\times 10^{-12}\ N {/eq}

• 5.

A particle that has a charge of {eq}1.99\times 10^{-19} C {/eq} moves perpendicularly at {eq}2.2\times 10^6\ m/s {/eq} towards a magnetic field formed by a high voltage line 4 T. Find the magnetic force to which the particle is subjected.

• {eq}1.5\times 10^{-12}\ N {/eq}

• {eq}2.1\times 10^{-12}\ N {/eq}

• {eq}1.8\times 10^{-12}\ N {/eq}

• {eq}2.2\times 10^{-12}\ N {/eq}

• 6.

If we have a proton with a charge of {eq}1.602\times 10^{-19} C {/eq} and moves perpendicularly at {eq}3\times 10^6\ m/s {/eq} towards a magnetic field formed by electric transformers of 4.8 T. What would be the magnetic force that this proton receives.

• {eq}1.3\times 10^{-12}\ N {/eq}

• {eq}2\times 10^{-12}\ N {/eq}

• {eq}2.3\times 10^{-12}\ N {/eq}

• {eq}3\times 10^{-12}\ N {/eq}

• 7.

Find the magnetic force that a particle with a charge of {eq}5.59\times 10^{-19} C {/eq} supports if it moves perpendicularly at {eq}6.4\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 1.9 T.

• {eq}7.3\times 10^{-12}\ N {/eq}

• {eq}6.8\times 10^{-12}\ N {/eq}

• {eq}6.3\times 10^{-12}\ N {/eq}

• {eq}7.7\times 10^{-12}\ N {/eq}

• 8.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}6\times 10^6\ m/s {/eq} towards a magnetic field formed by a computer screen of 0.9 T. Calculate the magnetic force that the electron experiences.

• {eq}9.5\times 10^{-13}\ N {/eq}

• {eq}9.1\times 10^{-12}\ N {/eq}

• {eq}8.1\times 10^{-12}\ N {/eq}

• {eq}8.7\times 10^{-13}\ N {/eq}

• 9.

A particle charged with {eq}3.67\times 10^{-19} C {/eq} translates perpendicularly at {eq}6\times 10^6\ m/s {/eq} towards a magnetic field created by radio of 1.2 T. When calculating the magnetic force of this particle, the result would be?

• {eq}2.3\times 10^{-12}\ N {/eq}

• {eq}2.8\times 10^{-12}\ N {/eq}

• {eq}2.6\times 10^{-12}\ N {/eq}

• {eq}2.1\times 10^{-12}\ N {/eq}

• 10.

When calculating the magnetic force of a particle that has a charge of {eq}4.17\times 10^{-19} C {/eq} and moves perpendicularly at {eq}5.9\times 10^6\ m/s {/eq} towards a magnetic field generated by the Earth of 0.65 T. What would be the result?

• {eq}1.8\times 10^{-12}\ N {/eq}

• {eq}1.6\times 10^{-12}\ N {/eq}

• {eq}1.5\times 10^{-12}\ N {/eq}

• {eq}1.7\times 10^{-12}\ N {/eq}

• 11.

A particle that has a charge of {eq}2.457\times 10^{-19} C {/eq} moves perpendicularly at {eq}5.3\times 10^6\ m/s {/eq} towards a magnetic field formed by a high voltage line 2.7 T. Find the magnetic force to which the particle is subjected.

• {eq}3.9\times 10^{-12}\ N {/eq}

• {eq}5.6\times 10^{-12}\ N {/eq}

• {eq}3.5\times 10^{-12}\ N {/eq}

• {eq}5.6\times 10^{-12}\ N {/eq}

• 12.

Calculate the magnetic force that a particle with a charge of {eq}5.04\times 10^{-19} C {/eq} experiences and that moves perpendicularly at {eq}6.4\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 6.7 T.

• {eq}1.1\times 10^{-12}\ N {/eq}

• {eq}3.3\times 10^{-12}\ N {/eq}

• {eq}2.2\times 10^{-11}\ N {/eq}

• {eq}3.3\times 10^{-11}\ N {/eq}

• 13.

Find the magnetic force that a particle with a charge of {eq}8.11\times 10^{-19} C {/eq} supports if it moves perpendicularly at {eq}4\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 1.9 T.

• {eq}6.2\times 10^{-12}\ N {/eq}

• {eq}5.8\times 10^{-12}\ N {/eq}

• {eq}4.9\times 10^{-12}\ N {/eq}

• {eq}6.6\times 10^{-12}\ N {/eq}

• 14.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}1.7\times 10^6\ m/s {/eq} towards a magnetic field formed by a computer screen of 0.6 T. Calculate the magnetic force that the electron experiences.

• {eq}3\times 10^{-13}\ N {/eq}

• {eq}3.2\times 10^{-13}\ N {/eq}

• {eq}1.6\times 10^{-13}\ N {/eq}

• {eq}3.5\times 10^{-13}\ N {/eq}

• 15.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}4.4\times 10^6\ m/s {/eq} towards a magnetic field formed by two magnets of 1.4 T. Calculate the magnetic force that the electron experiences.

• {eq}1.1\times 10^{-13}\ N {/eq}

• {eq}9.9\times 10^{-13}\ N {/eq}

• {eq}8.8\times 10^{-13}\ N {/eq}

• {eq}1.1\times 10^{-12}\ N {/eq}

• 16.

What will be the magnetic force that has a particle charged with {eq}3.31\times 10^{-19} C {/eq} moving perpendicular to {eq}6.7\times 10^6\ m/s {/eq} towards a magnetic field of 4 T.

• {eq}9.1\times 10^{-12}\ N {/eq}

• {eq}7.7\times 10^{-12}\ N {/eq}

• {eq}8.9\times 10^{-12}\ N {/eq}

• {eq}8.2\times 10^{-12}\ N {/eq}

• 17.

When calculating the magnetic force of a particle that has a charge of {eq}2.58\times 10^{-19} C {/eq} and moves perpendicularly at {eq}4.6\times 10^6\ m/s {/eq} towards a magnetic field generated by the Earth of 0.4 T. What would be the result?

• {eq}4.7\times 10^{-13}\ N {/eq}

• {eq}5.3\times 10^{-12}\ N {/eq}

• {eq}6.8\times 10^{-13}\ N {/eq}

• {eq}5.3\times 10^{-13}\ N {/eq}

• 18.

A proton with a charge of {eq}1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}5.7\times 10^6\ m/s {/eq} and it moves to a magnetic field formed by a TV of 2.9 T. Determine the magnetic force that the proton experiences.

• {eq}1.5\times 10^{-12}\ N {/eq}

• {eq}0.6\times 10^{-12}\ N {/eq}

• {eq}1.1\times 10^{-12}\ N {/eq}

• {eq}2.6\times 10^{-12}\ N {/eq}

• 19.

A particle charged with {eq}6.31\times 10^{-19} C {/eq} translates perpendicularly at {eq}4.1\times 10^6\ m/s {/eq} towards a magnetic field created by radio of 3.7 T. When calculating the magnetic force of this particle, the result would be?

• {eq}10.6\times 10^{-12}\ N {/eq}

• {eq}9.6\times 10^{-12}\ N {/eq}

• {eq}9.1\times 10^{-12}\ N {/eq}

• {eq}10.2\times 10^{-12}\ N {/eq}

• 20.

If we have a proton with a charge of {eq}1.602\times 10^{-19} C {/eq} and moves perpendicularly at {eq}6\times 10^6\ m/s {/eq} towards a magnetic field formed by electric transformers of 4.2 T. What would be the magnetic force that this proton receives.

• {eq}5.0\times 10^{-12}\ N {/eq}

• {eq}3.0\times 10^{-12}\ N {/eq}

• {eq}4.0\times 10^{-12}\ N {/eq}

• {eq}2.0\times 10^{-12}\ N {/eq}

• 21.

A proton with a charge of {eq}1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}6.9\times 10^6\ m/s {/eq} and it moves to a magnetic field formed by a TV of 0.9 T. Determine the magnetic force that the proton experiences.

• {eq}1.2\times 10^{-12}\ N {/eq}

• {eq}1.9\times 10^{-15}\ N {/eq}

• {eq}1.1\times 10^{-13}\ N {/eq}

• {eq}9.9\times 10^{-13}\ N {/eq}

• 22.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}6.1\times 10^6\ m/s {/eq} towards a magnetic field formed by a computer screen of 5 T. Calculate the magnetic force that the electron experiences.

• {eq}2.9\times 10^{-12}\ N {/eq}

• {eq}4.1\times 10^{-12}\ N {/eq}

• {eq}4.9\times 10^{-12}\ N {/eq}

• {eq}1.5\times 10^{-12}\ N {/eq}

• 23.

If we have a proton with a charge of {eq}1.602\times 10^{-19} C {/eq} and moves perpendicularly at {eq}3\times 10^6\ m/s {/eq} towards a magnetic field formed by electric transformers of 8.4 T. What would be the magnetic force that this proton receives.

• {eq}3.9\times 10^{-12}\ N {/eq}

• {eq}4.7\times 10^{-12}\ N {/eq}

• {eq}4.0\times 10^{-12}\ N {/eq}

• {eq}4.8\times 10^{-12}\ N {/eq}

• 24.

A particle that has a charge of {eq}2.89\times 10^{-19} C {/eq} moves perpendicularly at {eq}8.0\times 10^5\ m/s {/eq} towards a magnetic field formed by a high voltage line 6 T. Find the magnetic force to which the particle is subjected.

• {eq}1.4\times 10^{-12}\ N {/eq}

• {eq}1.7\times 10^{-12}\ N {/eq}

• {eq}1.6\times 10^{-12}\ N {/eq}

• {eq}1.5\times 10^{-12}\ N {/eq}

• 25.

When calculating the magnetic force of a particle that has a charge of {eq}5.20\times 10^{-19} C {/eq} and moves perpendicularly at {eq}9.0\times 10^5\ m/s {/eq} towards a magnetic field generated by the Earth of 0.5 T. What would be the result?

• {eq}1.5\times 10^{-13}\ N {/eq}

• {eq}1.5\times 10^{-12}\ N {/eq}

• {eq}2.3\times 10^{-13}\ N {/eq}

• {eq}2.3\times 10^{-12}\ N {/eq}

• 26.

What will be the magnetic force that has a particle charged with {eq}3.98\times 10^{-19} C {/eq} moving perpendicular to {eq}8.62\times 10^6\ m/s {/eq} towards a magnetic field of 8 T.

• {eq}2.7\times 10^{-11}\ N {/eq}

• {eq}2.7\times 10^{-10}\ N {/eq}

• {eq}2.7\times 10^{-13}\ N {/eq}

• {eq}2.7\times 10^{-12}\ N {/eq}

• 27.

Find the magnetic force that a particle with a charge of {eq}6.87\times 10^{-19} C {/eq} supports if it moves perpendicularly at {eq}8.2\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 3.4 T.

• {eq}1.9\times 10^{-11}\ N {/eq}

• {eq}2.2\times 10^{-11}\ N {/eq}

• {eq}1.2\times 10^{-11}\ N {/eq}

• {eq}1.5\times 10^{-11}\ N {/eq}

• 28.

An electron with a charge of {eq}-1.602\times 10^{-19} C {/eq} moves perpendicularly at {eq}9\times 10^6\ m/s {/eq} towards a magnetic field formed by two magnets of 2.7 T. Calculate the magnetic force that the electron experiences.

• {eq}3.9\times 10^{-12}\ N {/eq}

• {eq}4.8\times 10^{-12}\ N {/eq}

• {eq}4.5\times 10^{-12}\ N {/eq}

• {eq}4.1\times 10^{-12}\ N {/eq}

• 29.

A particle charged with {eq}5.11\times 10^{-19} C {/eq} translates perpendicularly at {eq}6.2\times 10^6\ m/s {/eq} towards a magnetic field created by radio of 4 T. When calculating the magnetic force of this particle, the result would be?

• {eq}1.2\times 10^{-11}\ N {/eq}

• {eq}0.6\times 10^{-11}\ N {/eq}

• {eq}1.3\times 10^{-11}\ N {/eq}

• {eq}0.9\times 10^{-11}\ N {/eq}

• 30.

Calculate the magnetic force that a particle with a charge of {eq}9\times 10^{-19} C {/eq} experiences and that moves perpendicularly at {eq}2.3\times 10^6\ m/s {/eq} and is heading towards a magnetic field of 9 T.