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Normal vs. Inverse Normal Distribution | Overview & Formula

Oliver Morrison, Gerald Lemay, Christianlly Cena
  • Author
    Oliver Morrison

    Oliver Morrison has two degrees from California Polytechnic State University; there are a Master's and a Bachelor's in Aerospace Engineering. He has two years of teaching experience at the college level in subjects such as Engineering, Higher Math, Astrophysics, and more. He is also a published author to 3 scientific papers in the subject of Aerospace Engineering.

  • Instructor
    Gerald Lemay

    Gerald has taught engineering, math and science and has a doctorate in electrical engineering.

  • Expert Contributor
    Christianlly Cena

    Christianlly has taught college Physics, Natural science, Earth science, and facilitated laboratory courses. He has a master's degree in Physics and is currently pursuing his doctorate degree.

Understand the differences between calculating the normal and the inverse normal distributions. Discover what the inverse cumulative distribution function represents. See examples of inverse Gaussian distribution or reverse bell curve. Updated: 11/21/2023
  • FAQs
  • Activities

Inverse Normal Probability: True or False Activity

This activity will help you assess your knowledge regarding the normal probability density function and the steps in calculating the inverse normal probability value.

Directions

Based on the given narrative, determine whether the following statements are TRUE or FALSE. To do this, print or copy this page on a blank paper and underline or circle the answer.

Helena weighs the frogs in a pond, obtaining a mean of 53 grams and a standard deviation of 8 grams. The weights followed a normal distribution, and there were 512 frogs in the population.

True | False 1. An inverse normal distribution is also known as a Gaussian distribution.

True | False 2. The sum of the probabilities of the frog weights would always be either 0 or 1.

True | False 3. An expression given as P(X < 53) can be composed as 1 - P(X > 53).

True | False 4. To know how many frogs are 80 grams or greater, Helena must use the concept of inverse normal probability.

True | False 5. The graph of the frog weights will trace a bell curve.

True | False 6. The standard deviation is depicted as the maximum point in the distribution of frog weights.

True | False 7. Helena can use the inverse normal probability only if the normal probability is unknown.

True | False 8. The given equation below is incorrect.


Answer Key

  1. False, because the correct statement is: A normal distribution is also known as a Gaussian distribution.
  2. False, because the correct statement is: The sum of the probabilities of the frog weights would always be 1.
  3. True
  4. True
  5. True
  6. False, because the correct statement is: The mean is depicted as the maximum point in the distribution of frog weights.
  7. False, because the correct statement is: Helena can use the inverse normal probability only if the normal probability is known.
  8. True

How do you find the inverse of a cumulative normal distribution?

Finding the inverse of a cumulative normal distribution involves determining the upper limit on a set of continuous outcomes in the normal distribution. The set of outcomes represents a specified probability that is transformed to a z-score via a z-table. The resulting z-score is then translated to the bound through the formula defining the z-score.

What does the inverse normal distribution tell you?

The inverse normal distribution illustrates how the probability of a continuous set of outcomes is related to the range for which those outcomes can occur. It transforms probability of the set to the bounds of the set.

How do you find the inverse of a normal distribution?

Finding the inverse of the normal distribution involves determining the range for a specific continuous set of outcomes within the normal distribution. To find the inverse, the probability of this set of outcomes is transformed into z-scores at each percentile of the range using a z-table. The resulting z-scores are then mapped to the bounds through the definition of a z-score. These resultant bounds precisely define the range.

The normal distribution describes a distribution of probabilities that follow a well-defined behavior. Sometimes also referred to as Gaussian distribution or bell-curve distribution, the normal distribution helps determine the likelihood of a range of possibilities, rather than a single outcome. Two factors determine the characteristics of the distribution; which are mean {eq}(\mu) {/eq} and standard deviation {eq}(\sigma) {/eq}. These are effectively the most likely outcome and how likely it is for a result to deviate from that outcome.

In general, the normal distribution is generated by the equation:

{eq}f(X) = \frac{1}{\sigma \sqrt{2\pi}} e^{-\frac{1}{2}\left(\frac{X - \mu}{\sigma}\right)^2} {/eq}

Normal Distribution Curve

Example of normal distribution curve with a mean of 0 and standard deviation of 1.

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Your next lesson will play in 10 seconds
  • 0:04 Normal Probability Density
  • 1:39 Finding the Inverse
  • 4:02 The Last Members
  • 4:56 Is There a Quorum?
  • 6:09 Lesson Summary

Where the normal distribution aims to calculate the probability of an event given an outcome, the inverse normal distribution formula provides a method for determining an outcome given a probability. Z-scores provide the best tool for performing both operations. The relations between Z and P are defined in "z-tables" which provide a direct, numerical conversion between the two concepts. It does not represent a formula but serves as a look-up tool that works in both directions. A useful program for generating z-tables is Microsoft Excel; The "NORMSDIST()" and "NORMSINV()" functions provide conversions from z-score to probability and the reverse respectively.

For the inverse distribution formula, given a probability of an outcome within an unknown range {eq}(-\infty, X) {/eq}, the z-score can be found from a z-table by looking up that particular probability (or the closest value to it); or in Excel by: {eq}Z = NORMSINV(P) {/eq}. After which, the bound, X, can be calculated by:

{eq}X = Z\sigma + \mu {/eq}

The cumulative distribution defines the probability of an event, X, occurring below a certain bound, a, in a normal distribution. The cumulative distribution formula can be written formally as:

{eq}P(X \leq a) = \int_{-\infty}^{a} f(X) dX {/eq}

Cumulative Distribution Curve

Cumulative distribution curve of a normal distribution with a mean of 0 and standard deviation of 1.

Since the entire area under the normal distribution curve is known to be 1, it is also possible to find the area under the curve of everything greater than the bound a through:

{eq}P(X \geq a) = 1 - P(X \leq a) {/eq}

Furthermore, the formula for a probability between two finite bounds can be re-written as:

{eq}P(a < X < b) = P(X < b) - P(X < a) {/eq}

The process of determining the cumulative distribution probability makes excellent use of the z-score conversion, avoiding integration. By finding the z-score associated with a, and then converting with the z-table, it immediately returns the associated probability. The probability can also be written with Z directly, by:

{eq}P(X \leq a) = P(Z \leq \frac{a - \mu}{\sigma}) {/eq}

The inverse cumulative distribution formula is simply the previous process put into reverse. Given a particular probability of an event occurring below an unknown bound a, Z can be immediately retrieved through a z-table, and converted to a through: {eq}a = Z\sigma + \mu {/eq}.

Using Inverse Gaussian Distribution

The inverse Gaussian distribution (or inverse normal distribution) is used for calculating the percentiles of many different data sets. Percentiles are just a measure of how much of the data is predicted to occur below a certain point. The inverse cumulative distribution is very helpful in determining such percentiles.

Example. A biologist is studying the lifespans of a population of rabbits. They determine that the mean lifetime is about 9 years ({eq}\mu = 9 {/eq}) and a standard deviation of 1 year ({eq}\sigma = 1 {/eq}). They want to find the 25th and 75th percentiles of the lifetime.

They notice that the values they want to calculate are related to the probabilities: {eq}P(X < a) = 0.25 {/eq} and {eq}P(X < b) = 0.75 {/eq}, and they must determine the bounds a and b.

We can calculate normal distribution (probability) and inverse normal distribution (z-score) using a graphing display calculator. The procedure is explained for two of the most commonly used calculators here.

Using TI - 84

The normal distribution (also called Gaussian distribution or bell-curve distribution) is useful for interpreting probabilities of a range of events and its shape is determined by the mean and standard deviation. A probability is represented by the area under the curve in such a range. The inverse normal distribution provides a method for determining the range of data given a probability. Through the use of z-scores & z-tables, the range and probability can be determined from each other, allowing both processes to be performed. The cumulative distribution provides the probability of any outcome occurring below a certain bound while the inverse cumulative distribution finds the bound given a probability below that bound.

Video Transcript

Normal Probability Density

Fred has just joined a large group of bird watchers. Although the general meeting for the group is scheduled to start at 7 PM, the meeting begins much later. This is a non-punctual group! Fred decides to use arrival times to play with some of the math he has recently learned. Let's follow Fred as he attempts to understand the behavior of this group.

There are 1,000 members who regularly attend the monthly meetings. Fred gets to the meeting place early and keeps a running record of arrival times relative to the 7 PM start time. The mean of these arrival times, μ, is 15 minutes. In other words, on average, people show up 15 minutes late. The standard deviation, σ, of Fred's data is 5 minutes.

After plotting the data, Fred sees a familiar bell-shaped curve, the normal probability density function, also known as the Gaussian distribution.


The peak located at the mean of 15
The_peak_located_at_the_mean_of_15


This is an idealized curve. Fred's data roughly resembles this curve. The area under the curve is a probability. Integrating from -∞ to +∞ include all the arrival times, and the probability is 1.

The X on the horizontal axis is the random variable X. We can ask a question like, ''What is the probability the random variable X (i.e., the arrival time) is less than some value?'' In the figure, there is an orange shaded area. This area is the probability the person will arrive less than 5 minutes late. Now, let's ask this type of question in a slightly different way.

Finding the Inverse

Fred would like to know at what time, a, there will be less than 23 members present. This is a probability of 23 / 1,000 = 0.023. Thus, we are asking for the value of X, which will give an area under the curve equal to our given value, or in this case, 0.023. This is the inverse normal probability value. We can write this as P(X < a) = 0.023.

This 0.023 probability is the area under the curve. In principle, we would integrate the normal curve from -∞ to a. The problems are we don't know a, and the integral itself does not have a closed-form solution. We can use numerical methods to approximate the integration very accurately, but we won't have a result as a function of a. If we did, we could set this result equal to 0.023 and use algebra to solve for a.

Also, it would be impossible to tabulate all possible combinations of means and standard deviations. Instead, tables are published for a mean of 0 and a standard deviation of 1. The random variable is called Z. A portion of one of these tables looks like:


Area under the curve from negative infinity to the Z value
Area_under_the_curve_from_negative_infinity_to_the_Z_value


Fred looks at the table for the number closest to 0.023. He finds:

  • P = 0.0233 for Z = -1.99
  • P = 0.0228 for Z = -2.00
  • P = 0.0222 for Z = -2.01

Do you see how the numbers in the first column and the numbers in the first row are combined to locate a probability value? We choose the closest: Z = -2.00. Now to relate this value to our bird watchers group.

The relationship between the random variables X and Z:


null


In our case, μ = 15 and σ = 5:


null


Thus, (a - 15) / 5 = -2.00. Solving for a, we get a = 5.

Fred is deliriously happy! He expects to see at least 23 members present after waiting 5 minutes.

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